Function typedefs have any use?

Gabriel Dos Reis
Mon Feb 7 00:01:00 GMT 2005

"Kevin P. Fleming" <> writes:


| So, that leaves me back at my original quandary: I can create a
| typedef of a function type, and I can use that typedef to declare
| function pointers to hold addresses of compatible functions, but I
| can't use the typedef to actually _declare_ those compatible functions

sure, you can use it to declare the function itself.  See the example I

But, yes, you can't use it to *define* it.  Think about how you'd
introduce the function parameters.

-- Gaby

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