behavior of -D=FOO

Marty Leisner mleisner@eng.mc.xerox.com
Wed Dec 7 17:14:00 GMT 2005


What should the behavior be of -D=FOO?

gcc 2.9.5 says
	"malformed option '-D =FOO'

gcc 3 inserts
	#define FOO

when you do -DFOO it inserts
	#define FOO 1

Reading the documentation carefully, it looks like it expects
-D FOO
but I've been using
-DFOO
for years (the behavior is equivalent).



marty		mleisner@eng.mc.xerox.com   
Don't  confuse education with schooling.
	Milton Friedman to Yogi Berra



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