gcc and -fPIC
Gerhard Wiesinger
lists@wiesinger.com
Fri Oct 15 19:16:00 GMT 2004
On Fri, 15 Oct 2004, Jeffrey A Law wrote:
> On Fri, 2004-10-15 at 12:51, Gerhard Wiesinger wrote:
>> On Fri, 15 Oct 2004 bserdar@nc.rr.com wrote:
>>
>>>
>>>> 80485b3: e8 00 00 00 00 call 80485b8 <X::f()+0xc>
>>>> 80485b8: 5b pop %ebx
>>>> 80485b9: 81 c3 5c 12 00 00 add $0x125c,%ebx
>>>
>>> With pop ebx, it pops the eip at that instruction to ebx. I'm guessing it'll use ebx as a base pointer to data (or code?) from this point on. You can verify this guess by accessing some global variables from within X::f() and see whether it uses ebx-relative access.
>>>
>>
>> OK, but why is the function call at 80485b3 to the next address at
>> 80485b8?
> Because it allows us to get the current PC's value in a position
> independent way.
>
> ie, the call pushes the return address onto the stack and we pop
> that value into ebx.
>
OK, I got it now.
Thank you.
Ciao,
Gerhard
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