asm volatile encoding : Doubt.
Fri Mar 19 12:15:00 GMT 2004
The following is a line in rtems' timer driver
asm volatile(".byte 0x0F, 0x31" : "=A" (result));
I could not understand this. RTEMS mailing list
clarified me saying that it is encoding of pentium
rdtsc instruction. Please tell me how the above
statement differs from the one below.
(Assuming the instruction pnemonic is correct)
Only thing I found from gnu documentation for gcc
that '=' specifies that result is a output of the
instruction. According to the document, there must be
an instruction pnemonic string first inside the
paranthesis. But there is the directive .byte there.
Does this mean the opcode directly?
The document also says that the arguments can be
referred like %0, %1 etc. But there is nothing like
this here. Is it because, since there is only one
operand, it is assumed that it follows the opcode?
Please clear my doubts.
With Best Regards
Yahoo! India Insurance Special: Be informed on the best policies, services, tools and more.
Go to: http://in.insurance.yahoo.com/licspecial/index.html
More information about the Gcc-help