Warning with 64-Bit datatype

[Michael Pfeiffer]

Hi,

I get some warnings with following code:

__int64 hash;

hash=(hash<<1) & 0x7FFFFFFFFFFFFFFFL;

The warnings tell me that the constant is too long for the datatype of 
"hash". But when I count the digits of 0x7FFFFFFFFFFFFFFFL there are 
exactly 16 which are equal to 64 bit. It doesn't helps either when I 
change the datatype from __int64 to (unsigned) long long, so what could be 
the reason for this warning?

Michael

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