void template argument
Falk Hueffner
falk.hueffner@student.uni-tuebingen.de
Mon Oct 6 13:06:00 GMT 2003
"ëÃÃÃÃÃ
ÃÃà ð.ç." <kravchenko@land.ru> writes:
> #ifdef TEMPLATE
> template<class arg>
> class At {
> public:
> void a(arg) {cout << "a" << endl; }
> };
> typedef At<void> A;
> #else
> class A {
> public:
> void a(void) {cout << "a" << endl; }
> };
> #endif
>
> i've supposed that two banches (with and without
> -DTEMAPLTE) are identical. but gcc 2.95.3 & 3.2.3
> compilers fails compiling -DTEMPLATE with errors.
void a(void) does not declare a nameless parameter of type void, but
as a special case (inherited from C) declares a function without
parameters. Since this happens at the syntactic level, the same is
not true for a template argument.
--
Falk
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