[Bug c++/78609] invalid member's visibility detection in constexpr with arrays
pinskia at gcc dot gnu.org
gcc-bugzilla@gcc.gnu.org
Fri Jul 23 20:15:17 GMT 2021
https://gcc.gnu.org/bugzilla/show_bug.cgi?id=78609
Andrew Pinski <pinskia at gcc dot gnu.org> changed:
What |Removed |Added
----------------------------------------------------------------------------
Last reconfirmed| |2021-07-23
Summary|invalid member's visibility |invalid member's visibility
|detection in constexpr |detection in constexpr with
| |arrays
Status|UNCONFIRMED |NEW
Ever confirmed|0 |1
--- Comment #3 from Andrew Pinski <pinskia at gcc dot gnu.org> ---
Confirmed. The problem is with taking the address of a field and templates.
Here is a reduced testcase:
struct A
{
private:
char data;
public:
constexpr const char *c_str() const { return &data; }
constexpr A(char const str) : data(str) {};
constexpr A() : data() {};
};
template<size_t>
struct B
{
static const constexpr A name = A{'a'};
static const constexpr char * value = name.c_str();
};
template<size_t I>
const constexpr A B<I>::name;
const char *c = B<0>::value;
---- CUT ----
If I make B a non-template, then it will work correctly.
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