[Bug fortran/95647] operator(.eq.) and operator(==) treated differently

cvs-commit at gcc dot gnu.org gcc-bugzilla@gcc.gnu.org
Fri Feb 12 21:05:28 GMT 2021


https://gcc.gnu.org/bugzilla/show_bug.cgi?id=95647

--- Comment #12 from CVS Commits <cvs-commit at gcc dot gnu.org> ---
The releases/gcc-10 branch has been updated by Jerry DeLisle
<jvdelisle@gcc.gnu.org>:

https://gcc.gnu.org/g:d5021162cf33081c128cd5c4f96ea0b7ca8739d7

commit r10-9365-gd5021162cf33081c128cd5c4f96ea0b7ca8739d7
Author: Steve Kargl <sgk@troutmask.apl.washington.edu>
Date:   Fri Feb 12 13:04:14 2021 -0800

    libgfortran: Fix PR95647 by changing the interfaces of operators .eq. and
.ne.

    The FE converts the old school .eq. to ==,
    and then tracks the ==.  The module starts with == and so it does not
    properly overload the .eq.  Reversing the interfaces fixes this.

    2021-02-12  Steve Kargl <sgk@troutmask.apl.washington.edu>

    libgfortran/ChangeLog:

            PR libfortran/95647
            * ieee/ieee_arithmetic.F90: Flip interfaces of operators .eq. to
            == and .ne. to /= .

    gcc/testsuite/ChangeLog:

            PR libfortran/95647
            * gfortran.dg/ieee/ieee_12.f90: New test.


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