[Bug fortran/96911] bug with Intrinsic shifta/shiftl/shiftr

[zhen.xu@compiler-dev.com]

https://gcc.gnu.org/bugzilla/show_bug.cgi?id=96911

--- Comment #4 from zhen.xu@compiler-dev.com ---
(In reply to kargl from comment #2)
> (In reply to zhen.xu from comment #0)
> > Dealing with Intrinsic shifta/shiftl/shiftr, gfortran refuses proper numbers
> > in the code below and throws "Error: Integer too big for its kind". 
> > 
> > The code is checked with ifort.
> > 
> > -------code----------
> > program test
> >   print *, shifta(-128_1, 1);
> >   print *, shifta(-32768_2, 1);
> >   print *, shifta(-2147483648_4, 1);
> >   print *, shifta(-9223372036854775808_8, 1);
> > 
> >   print *, shiftl(-128_1, 1);
> >   print *, shiftl(-32768_2, 1);
> >   print *, shiftl(-2147483648_4, 1);
> >   print *, shiftl(-9223372036854775808_8, 1);
> > 
> >   print *, shiftr(-128_1, 1);
> >   print *, shiftr(-32768_2, 1);
> >   print *, shiftr(-2147483648_4, 1);
> >   print *, shiftr(-9223372036854775808_8, 1);
> > 
> > end
> > ----------------------
> 
> There are no negative integer withs gfortran.  -128_1 is a unary minus
> operator and 128_1 is a invalid operand. 128_1 would be greater than
> huge(1_1).  The only way to get the most "negative integer" is
> to do -huge(1_1) - 1 (assuming twos-complement arithmetic applies).

But how can the code below be compiled by gfortran well and print out -128
properly?
--------------------
program testint
      integer(1) :: x = -128
      print *, x
end
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