[Bug tree-optimization/97555] [11 Regression] wrong code at -Os and above on x86_64-pc-linux-gnu since r11-3685
aldyh at gcc dot gnu.org
gcc-bugzilla@gcc.gnu.org
Mon Oct 26 16:57:30 GMT 2020
https://gcc.gnu.org/bugzilla/show_bug.cgi?id=97555
--- Comment #4 from Aldy Hernandez <aldyh at gcc dot gnu.org> ---
The problem here is we're trying to add 1 to a -1 in a signed 1-bit field.
Signed 1-bits are annoying because you can't really add or subtract one,
because the one is unrepresentable. For invert() we have a special
subtract_one() function that handles 1-bit signed fields. We need a
corresponding add_one() here.
The untested patch below should do it.
diff --git a/gcc/range-op.cc b/gcc/range-op.cc
index ee62f103598..74ab2e57fde 100644
--- a/gcc/range-op.cc
+++ b/gcc/range-op.cc
@@ -3680,15 +3680,28 @@ range_tests ()
// Test 1-bit signed integer union.
// [-1,-1] U [0,0] = VARYING.
tree one_bit_type = build_nonstandard_integer_type (1, 0);
+ tree one_bit_min = vrp_val_min (one_bit_type);
+ tree one_bit_max = vrp_val_max (one_bit_type);
{
- tree one_bit_min = vrp_val_min (one_bit_type);
- tree one_bit_max = vrp_val_max (one_bit_type);
int_range<2> min (one_bit_min, one_bit_min);
int_range<2> max (one_bit_max, one_bit_max);
max.union_ (min);
ASSERT_TRUE (max.varying_p ());
}
+ // Test inversion of 1-bit signed integers.
+ {
+ int_range<2> min (one_bit_min, one_bit_min);
+ int_range<2> max (one_bit_max, one_bit_max);
+ int_range<2> t;
+ t = min;
+ t.invert ();
+ ASSERT_TRUE (t == max);
+ t = max;
+ t.invert ();
+ ASSERT_TRUE (t == min);
+ }
+
// Test that NOT(255) is [0..254] in 8-bit land.
int_range<1> not_255 (UCHAR (255), UCHAR (255), VR_ANTI_RANGE);
ASSERT_TRUE (not_255 == int_range<1> (UCHAR (0), UCHAR (254)));
diff --git a/gcc/value-range.cc b/gcc/value-range.cc
index 7847104050c..f45a342605a 100644
--- a/gcc/value-range.cc
+++ b/gcc/value-range.cc
@@ -1772,18 +1772,29 @@ irange::irange_intersect (const irange &r)
verify_range ();
}
+// Signed 1-bits are strange. You can't subtract 1, because you can't
+// represent the number 1. This works around that for the invert routine.
+
static wide_int inline
subtract_one (const wide_int &x, tree type, wi::overflow_type &overflow)
{
- // A signed 1-bit bit-field, has a range of [-1,0] so subtracting +1
- // overflows, since +1 is unrepresentable. This is why we have an
- // addition of -1 here.
if (TYPE_SIGN (type) == SIGNED)
- return wi::add (x, -1 , SIGNED, &overflow);
+ return wi::add (x, -1, SIGNED, &overflow);
else
return wi::sub (x, 1, UNSIGNED, &overflow);
}
+// The analogous function for adding 1.
+
+static wide_int inline
+add_one (const wide_int &x, tree type, wi::overflow_type &overflow)
+{
+ if (TYPE_SIGN (type) == SIGNED)
+ return wi::sub (x, -1, SIGNED, &overflow);
+ else
+ return wi::add (x, 1, TYPE_SIGN (type), &overflow);
+}
+
/* Return the inverse of a range. */
void
@@ -1881,7 +1892,7 @@ irange::invert ()
// set the overflow bit.
if (type_max != wi::to_wide (orig_range.m_base[i]))
{
- tmp = wi::add (wi::to_wide (orig_range.m_base[i]), 1, sign, &ovf);
+ tmp = add_one (wi::to_wide (orig_range.m_base[i]), ttype, ovf);
m_base[nitems++] = wide_int_to_tree (ttype, tmp);
m_base[nitems++] = wide_int_to_tree (ttype, type_max);
if (ovf)
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