[Bug target/71436] [7 Regression] Segmentation fault in arm_output_multireg_pop

[ktkachov at gcc dot gnu.org]

https://gcc.gnu.org/bugzilla/show_bug.cgi?id=71436

--- Comment #6 from ktkachov at gcc dot gnu.org ---
>From what I can see *load_multiple is intended to catch load-multiple of more
than 4 registers (though it should work correctly for fewer than that).
In this case where we're loading 2 registers the *ldm2_ pattern from ldmstm.md
should be used. And indeed it is used in the early dumps:
(insn 27 23 28 4 (parallel [
            (set (reg:SI 0 r0)
                (mem/u/c:SI (reg/f:SI 147) [2 c+0 S4 A32]))
            (set (reg:SI 1 r1)
                (mem/u/c:SI (plus:SI (reg/f:SI 147)
                        (const_int 4 [0x4])) [2 c+4 S4 A32]))
        ]) "ldm.c":25 385 {*ldm2_}
     (nil))

but in 244r.loop2_invariant it is copied to before its basic block as:
(insn 55 19 67 3 (parallel [
            (set (reg:SI 0 r0)
                (mem/u/c:SI (reg/f:SI 147) [2 c+0 S4 A32]))
            (set (reg:SI 158)
                (mem/u/c:SI (plus:SI (reg/f:SI 147)
                        (const_int 4 [0x4])) [2 c+4 S4 A32]))
        ]) "ldm.c":25 404 {*load_multiple}
     (expr_list:REG_UNUSED (reg:SI 0 r0)
        (nil)))

and then *load_multiple is used for that copy.
I think *ldm2_ is not used for that copy because it requires its destination
register to be arm_hard_general_register_operand whereas in the copy reg 158 is
a pseudo