[Bug c++/69098] [6.0 regression] Member function pointer template flagged with 'is not a function template'
msebor at gcc dot gnu.org
gcc-bugzilla@gcc.gnu.org
Mon Jan 4 04:39:00 GMT 2016
https://gcc.gnu.org/bugzilla/show_bug.cgi?id=69098
Martin Sebor <msebor at gcc dot gnu.org> changed:
What |Removed |Added
----------------------------------------------------------------------------
Status|UNCONFIRMED |NEW
Last reconfirmed| |2016-01-04
CC| |msebor at gcc dot gnu.org
Known to work| |5.1.0
Summary|Member function pointer |[6.0 regression] Member
|template flagged with 'is |function pointer template
|not a function template' |flagged with 'is not a
| |function template'
Ever confirmed|0 |1
Known to fail| |6.0
--- Comment #2 from Martin Sebor <msebor at gcc dot gnu.org> ---
Confirmed. The following simplified test case also reproduces the error with
today's top of trunk. 5.1.0 compiles the test case successfully so this is a
regression.
$ cat u.cpp && /home/msebor/build/gcc-trunk-svn/gcc/xg++
-B/home/msebor/build/gcc-trunk-svn/gcc -S -Wall -Wextra -o/dev/null -std=c++14
u.cpp
struct A
{
template <int>
static void (*pf)();
};
template <int>
void foo () {
(void)A::pf<true>;
}
void bar () {
foo<0>();
}
u.cpp: In instantiation of ‘void foo() [with int <anonymous> = 0]’:
u.cpp:13:10: required from here
u.cpp:9:9: error: ‘template<int <anonymous> > void (* A::pf)()<<anonymous> >’
is not a function template
(void)A::pf<true>;
^
u.cpp:9:9: error: ‘pf<true>’ is not a member of ‘A’
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