[Bug c++/68148] New: Devirtualization only applies to last of multiple successive calls
matt at godbolt dot org
gcc-bugzilla@gcc.gnu.org
Thu Oct 29 15:49:00 GMT 2015
https://gcc.gnu.org/bugzilla/show_bug.cgi?id=68148
Bug ID: 68148
Summary: Devirtualization only applies to last of multiple
successive calls
Product: gcc
Version: 5.2.0
Status: UNCONFIRMED
Severity: normal
Priority: P3
Component: c++
Assignee: unassigned at gcc dot gnu.org
Reporter: matt at godbolt dot org
Target Milestone: ---
Given the code:
----
struct Interface {
virtual ~Interface() {}
virtual void virtualFunc() = 0;
virtual void virtualFunc2() = 0;
};
struct Concrete : Interface {
int counter_;
Concrete() : counter_(0) {}
void virtualFunc() { counter_++; }
void virtualFunc2() { counter_++; }
};
void test(Interface &c) {
c.virtualFunc();
c.virtualFunc2();
}
----
(Compiled at -O3 -fdevirtualize-speculatively)
Speculative devirtualization is applied to the call to virtualFunc2, but not to
virtualFunc. (See https://goo.gl/Vtx5Fe). If one comments out the call to
virtualFunc2, then the virtualFunc() call *is* speculatively devirtualized
(https://goo.gl/G8f505).
It seems to me that either both should be spec devirtualized, or none. Or
perhaps even more generally, if the vtable pointer is that of "Concrete" then
both calls can be inlined in one and converted to counter+=2 (provided
inspection proved that Concrete's virtualFunc() does not modify the vtable,
which I believe is otherwise a barrier to this kind of optimization).
Am I missing something here, or is this a missed opportunity?
Thanks, Matt
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