[Bug c++/65354] New: Converting lambda to pointer results in double destruction

[charlie at charliedyson dot net]

https://gcc.gnu.org/bugzilla/show_bug.cgi?id=65354

            Bug ID: 65354
           Summary: Converting lambda to pointer results in double
                    destruction
           Product: gcc
           Version: 4.8.2
            Status: UNCONFIRMED
          Severity: normal
          Priority: P3
         Component: c++
          Assignee: unassigned at gcc dot gnu.org
          Reporter: charlie at charliedyson dot net

In the following, the unique_ptr is deleted twice if the lambda is converted to
a function pointer (#if 1) but runs without error if left as a lambda.

Compiled with g++-4.8 test.cpp -o test -std=c++1y on Linux Mint 17 x64.

I get the following output in the function pointer case:
Bye
Bye
*** Error in `./test': double free or corruption (fasttop): 0x0000000001e5c010
***
Aborted

Here's the code:

#include <memory>
#include <iostream>

struct X
{
    ~X () { std::cout << "Bye" << std::endl; }
};

struct Y
{
    explicit Y (std::unique_ptr<X> x)
    : m_x (std::move (x))
    { }

    std::unique_ptr<X> m_x;
};

int main ()
{
    using F = Y (*) (std::unique_ptr<X>);
    auto p = std::unique_ptr<X> {new X};

#if 1
    F f =
#else
    auto f =
#endif
    [] (std::unique_ptr<X> x)
    {
        return Y (std::move (x));
    };
    f (std::move (p));
}