[Bug tree-optimization/61384] New: ICE on valid code at -O3 on x86_64-linux-gnu
su at cs dot ucdavis.edu
gcc-bugzilla@gcc.gnu.org
Mon Jun 2 04:30:00 GMT 2014
https://gcc.gnu.org/bugzilla/show_bug.cgi?id=61384
Bug ID: 61384
Summary: ICE on valid code at -O3 on x86_64-linux-gnu
Product: gcc
Version: unknown
Status: UNCONFIRMED
Severity: normal
Priority: P3
Component: tree-optimization
Assignee: unassigned at gcc dot gnu.org
Reporter: su at cs dot ucdavis.edu
The following code causes an ICE when compiled with the current gcc trunk at
-O3 on x86_64-linux-gnu in both 32-bit and 64-bit modes.
It is a regression from 4.9.x.
$ gcc-trunk -v
Using built-in specs.
COLLECT_GCC=gcc-trunk
COLLECT_LTO_WRAPPER=/usr/local/gcc-trunk/libexec/gcc/x86_64-unknown-linux-gnu/4.10.0/lto-wrapper
Target: x86_64-unknown-linux-gnu
Configured with: ../gcc-trunk/configure --prefix=/usr/local/gcc-trunk
--enable-languages=c,c++ --disable-werror --enable-multilib
Thread model: posix
gcc version 4.10.0 20140601 (experimental) [trunk revision 211115] (GCC)
$
$ gcc-trunk -O2 small.c; a.out
$ gcc-4.9.0 -O3 small.c; a.out
$
$ gcc-trunk -O3 small.c
small.c: In function ‘fn2’:
small.c:11:1: internal compiler error: in check_probability, at
basic-block.h:953
fn2 ()
^
0xb8f066 check_probability
../../gcc-trunk/gcc/basic-block.h:953
0xb8c78f check_probability
../../gcc-trunk/gcc/tree.h:2842
0xb8c78f combine_probabilities
../../gcc-trunk/gcc/basic-block.h:962
0xb8c78f slpeel_tree_peel_loop_to_edge
../../gcc-trunk/gcc/tree-vect-loop-manip.c:1371
0xb8cbd4 vect_do_peeling_for_loop_bound(_loop_vec_info*, tree_node*,
tree_node*, unsigned int, bool)
../../gcc-trunk/gcc/tree-vect-loop-manip.c:1761
0xb7dba6 vect_transform_loop(_loop_vec_info*)
../../gcc-trunk/gcc/tree-vect-loop.c:5852
0xb9ac16 vectorize_loops()
../../gcc-trunk/gcc/tree-vectorizer.c:476
Please submit a full bug report,
with preprocessed source if appropriate.
Please include the complete backtrace with any bug report.
See <http://gcc.gnu.org/bugs.html> for instructions.
$
----------------------------
int a, b, d, e, g, h;
static int c = 1, f[5];
int
fn1 (int p1, int p2)
{
return p1 && p2 && p2;
}
void
fn2 ()
{
for (d = 0; d < 1; d++)
{
g = f[0];
e = 0;
h = fn1 (1, (a && c) ^ b);
}
for (; e < 5; e++)
f[e] = 1;
}
int
main ()
{
fn2 ();
return 0;
}
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