[Bug c++/54310] New: Order of operations during overload resolution
zeratul976 at hotmail dot com
gcc-bugzilla@gcc.gnu.org
Sat Aug 18 08:04:00 GMT 2012
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=54310
Bug #: 54310
Summary: Order of operations during overload resolution
Classification: Unclassified
Product: gcc
Version: 4.8.0
Status: UNCONFIRMED
Severity: normal
Priority: P3
Component: c++
AssignedTo: unassigned@gcc.gnu.org
ReportedBy: zeratul976@hotmail.com
GCC accepts the following code:
template <typename T>
struct meta
{
typedef typename T::type type;
};
struct S{};
template <typename T>
typename meta<T>::type foo(T, S);
int foo(int, int);
int main()
{
foo(0, 0);
}
Clang rejects this code with the following error:
test.cpp:4:22: error: type 'int' cannot be used prior to '::' because it has no
members
typedef typename T::type type;
^
test.cpp:10:10: note: in instantiation of template class 'meta<int>' requested
here
typename meta<T>::type foo(T, S);
^
test.cpp:10:24: note: while substituting deduced template arguments into
function template 'foo' [with T = int]
typename meta<T>::type foo(T, S);
^
I believe the code is invalid (and clang's error is correct), for the following
reasons:
1. Template argument deduction should be performed on the template candidate
*before* to discarding it due to a type mismatch for the second parameter
(expected S, got int). Section 13.3.1/7 of the standard says (emphasis mine):
"In each case where a candidate is a function template, candidate function
template specializations are generated using template argument deduction. Those
candidates are *then* handled as candidate functions in the usual way. A given
name can refer to one or more function templates and also to a set of
overloaded non-template functions. In such a case, the candidate functions
generated from each function template are combined with the set of non-template
candidate functions."
2. Template argument deduction on the template candidate should fail with a
hard error (not SFINAE), because the error that occurs (T::type not being valid
for T = int) is not in the immediate context of the function type. (Section
14.8.2/8, emphasis mine: "If a substitution results in an invalid type or
expression, type deduction fails. [...] Only invalid types and expressions *in
the immediate context* of the function type and its template parameter types
can result in a deduction failure. [...]").
GCC does reject the following example:
template <typename T>
struct meta
{
typedef typename T::type type;
};
template <typename T>
typename meta<T>::type foo(T);
int foo(int);
int main()
{
foo(0);
}
With the following error:
test.cpp: In instantiation of 'struct meta<int>':
test.cpp:8:24: required by substitution of 'template<class T> typename
meta::type foo(T) [with T = int]'
test.cpp:14:10: required from here
test.cpp:4:30: error: 'int' is not a class, struct, or union type
typedef typename T::type type;
^
suggesting that GCC already obeys point (2) above, and therefore the problem is
likely to be with point (1).
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