[Bug c++/54180] New: a bug using strcat function - it depends on variable declare order, but it should not.

[lirex.software at gmail dot com]

http://gcc.gnu.org/bugzilla/show_bug.cgi?id=54180

             Bug #: 54180
           Summary: a bug using strcat function - it depends on variable
                    declare order, but it should not.
    Classification: Unclassified
           Product: gcc
           Version: unknown
            Status: UNCONFIRMED
          Severity: normal
          Priority: P3
         Component: c++
        AssignedTo: unassigned@gcc.gnu.org
        ReportedBy: lirex.software@gmail.com


Created attachment 27940
  --> http://gcc.gnu.org/bugzilla/attachment.cgi?id=27940
source file

Hello,

I want to report bugs:

I using gcc gcc-4.6.1 on Microsoft Windows XP (service pack 3)
the options of the compiler:
c++ -I"D:\Program Files\PostgreSQL\9.1\include" -L"D:\Program
Files\PostgreSQL\9.1\lib" -lpq -o %application_file% %application_file%.cpp
-Wl,--subsystem,windows -lgdi32 -lcomctl32 -D_WIN32_IE=0x0300

the complete command line that triggers the bug:
just a part of my code which handles a window key pressure

the compiler output (error messages, warnings, etc.); and:
it outputs not the value which is expected, but partially(!) the value of other
variable:
if it should display a date with SQL_date_begin it displays a part of SQL1
(I replaced almost everywhere the parrword needed to access my Postgre SQL
database)

the function strcat works only proper 
if I declare char variables as follow:

CHAR SQL_date_begin[10], SQL_date_end[10],SQL1[150], SQL_result[100];   

but no way if:
CHAR SQL1[150], SQL_date_begin[10], SQL_date_end[10], SQL_result[100];   

somewhy in second order it owerwrites value of SQL_date_begin

note:

to form the value of SQL_date_begin I use 
strcpy(SQL_date_begin,"");
    wsprintf(chBuffer,_T("%d"),date_time_begin.wYear);
    strcat(SQL_date_begin,chBuffer);
    strcat(SQL_date_begin,"-");
    ...(only a part)

Regards,
Denis Kolesnik.