[Bug libstdc++/1773] __cplusplus defined to 1, should be 199711L

[tortoise_74 at yahoo dot co.uk]

http://gcc.gnu.org/bugzilla/show_bug.cgi?id=1773

Bruce Adams <tortoise_74 at yahoo dot co.uk> changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
                 CC|                            |tortoise_74 at yahoo dot
                   |                            |co.uk

--- Comment #124 from Bruce Adams <tortoise_74 at yahoo dot co.uk> 2011-11-25 18:33:25 UTC ---
My understanding of the last comment is that for -std=c++11 _cplusplus should
be set so that "#if __cplusplus > 201100L" can be used to conditionally compile
as C++03 vs C++11. 
I would expect this to be in the snapshot I'm using but it doesn't seem to be.
Has it regressed or do we need to wait for the next snapshot release?
What other way is there to distinguish C++03 and C++11 in source as a
workaround?

#include <iostream>

int main(int argc, char* argv[])
{
   std::cout << __cplusplus << std::endl;
   return 0;
}

#!/bin/sh

gcc --version
gcc -Wconversion blah.cpp -oblah -lstdc++
./blah

export LD_LIBRARY_PATH=/opt/gcc4.7/lib:$LD_LIBRARY_PATH
export PATH=/opt/gcc4.7/bin:$PATH
/opt/gcc4.7/bin/gcc --version
/opt/gcc4.7/bin/gcc -std=c++03 blah.cpp -oblah2  -lstdc++
./blah

gcc (GCC) 4.1.2 20080704 (Red Hat 4.1.2-51)
[snip]
1

gcc (GCC) 4.7.0 20111119 (experimental)
[snip]
1