[Bug c++/49813] [C++0x] sinh vs asinh vs constexpr

[rguenther at suse dot de]

http://gcc.gnu.org/bugzilla/show_bug.cgi?id=49813

--- Comment #6 from rguenther at suse dot de <rguenther at suse dot de> 2011-07-22 10:56:51 UTC ---
On Fri, 22 Jul 2011, paolo.carlini at oracle dot com wrote:

> http://gcc.gnu.org/bugzilla/show_bug.cgi?id=49813
> 
> --- Comment #5 from Paolo Carlini <paolo.carlini at oracle dot com> 2011-07-22 10:52:03 UTC ---
> We don't want this to depend on -std=gnu++0x vs -std=c++0x!!
> 
> The function is there, declared and callable, as removing constexpr reveals,
> the behavior wrt constexpr data cannot depend on __STRICT_ANSI__.

No, with -std=c++0x asinh is not declared and I get the error above.
With -std=gnu++0x the testcase works for me, even with constexpr.

No bug here.