[Bug libstdc++/48398] New: [C++0x] std::unique_ptr<T, D> is broken when D::pointer is not T*

[gintensubaru at gmail dot com]

http://gcc.gnu.org/bugzilla/show_bug.cgi?id=48398

           Summary: [C++0x] std::unique_ptr<T, D> is broken when
                    D::pointer is not T*
           Product: gcc
           Version: 4.6.0
            Status: UNCONFIRMED
          Severity: normal
          Priority: P3
         Component: libstdc++
        AssignedTo: unassigned@gcc.gnu.org
        ReportedBy: gintensubaru@gmail.com


example:

------------------------------------------------------------

#include <memory>
#include <cassert>

struct my_deleter
{
  typedef int* pointer;

  void operator()( pointer p ) {
    delete p;
  }

};

int main()
{
  std::unique_ptr<void, my_deleter> p( new int() );

  assert( p.get() != 0 ); // invalid conversion from 'void*' to 'int*'
  p.reset(); // no matching function for call to 'swap( void*&, int*& )'
}

------------------------------------------------------------


proposed patch:

--- libstdc++-v3/include/bits/unique_ptr.h
+++ libstdc++-v3/include/bits/unique_ptr.h
@@ -100,7 +100,7 @@ _GLIBCXX_BEGIN_NAMESPACE_VERSION
     typedef decltype( __test<_Del>(0)) type;
       };

-      typedef std::tuple<_Tp*, _Dp>      __tuple_type;
+      typedef std::tuple<typename _Pointer::type, _Dp>      __tuple_type;
       __tuple_type             _M_t;

     public: