[Bug libstdc++/23271] Members of ctype_base appear not to be integral constant expressions.

[davek at gcc dot gnu dot org]

------- Comment #9 from davek at gcc dot gnu dot org  2010-02-15 17:32 -------
(In reply to comment #5)
> Is the print member really already overflowed?  It has a value of 0200 which is
> 0x80: so if char is signed (it is on cygwin) then it's setting the sign bit,
> which should be OK I think.  

No, it isn't.  A signed char can contain values between 0x7f and -0x80. 
Assigning a value of +0x80 to it results in overflow.  You could assign
(char)0x80 to it and it would be ok, but 0x80 by itself isn't a constant that
will fit in a signed char, so it does need the cast (or to be expressed as the
negative equivalent.)


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http://gcc.gnu.org/bugzilla/show_bug.cgi?id=23271