[Bug target/31006] long double constant is read as double in i386

[ubizjak at gmail dot com]

------- Comment #6 from ubizjak at gmail dot com  2009-09-17 12:46 -------
Your d_a is defined as double, so gcc truncates constant to fit in the "double"
value range. After that, you pass this double value as an argument to %Lf,
which is wrong. You should write:

        printf("long double - double double = %+5.30Lf\n", (long double) d_a);

As far as your testcse is concerned, there is no error, truncation from long
double to double is what you requested with "double" intermediate register.


-- 

ubizjak at gmail dot com changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
             Status|UNCONFIRMED                 |RESOLVED
         Resolution|                            |INVALID


http://gcc.gnu.org/bugzilla/show_bug.cgi?id=31006