[Bug c/41942] New: __attribute__ ((visibility)) weird with functions returning pointers
eike at sf-mail dot de
gcc-bugzilla@gcc.gnu.org
Wed Nov 4 18:30:00 GMT 2009
const char * __attribute__ ((visibility ("hidden"))) foo(void)
{ return "foo"; }
const char __attribute__ ((visibility ("hidden"))) * bar(void)
{ return "bar"; }
Compile this with:
gcc -fPIC -Wl,--version-script=foobar.map -Wl,--strip-all -shared -o foobar.so
foobar.c
foo() now issues the warning "warning: Âvisibility attribute ignored on
non-class types" and the visibility is not applied. Placing the attribute at
that position is very unintuitive and the warning isn't particular helpful.
Also I found nothing in the documentation about this.
--
Summary: __attribute__ ((visibility)) weird with functions
returning pointers
Product: gcc
Version: 4.3.2
Status: UNCONFIRMED
Severity: normal
Priority: P3
Component: c
AssignedTo: unassigned at gcc dot gnu dot org
ReportedBy: eike at sf-mail dot de
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=41942
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