[Bug c/41055] New: libgcc functions and -mregparm don't work well together

[patrick dot georgi at coresystems dot de]

When building code with -mregparm=x on i?86 which uses libgcc functions (eg.
udivdi3), the calls to the libgcc functions use the calling convention as given
by mregparm, even though libgcc is internal to the compiler (and the user has
no ultimate control about when it is used).

Adding the compiler-native calling convention as regparm attribute to all calls
that are synthesized by the compiler might fix the problem.

The following shell script exhibits the problem.

cat > test.c << EOF
int main() {
 long long a= 4000000000;
 return a / 43937;
}
EOF

gcc -S test.c
mv test.s test.default.s

gcc -mregparm=3 -S test.c
mv test.s test.mregparm3.s

diff -u test.default.s test.mregparm3.s
exit 0
# there should be no difference in the calling convention
# as __divdi3 is taken from libgcc, but I get the result:
--- test.default.s      Do. Aug 13 15:47:28 2009
+++ test.mregparm3.s    Do. Aug 13 15:47:28 2009
 -18,10 +18,9 @@
        movl    $0, -4(%ebp)
        movl    -8(%ebp), %eax
        movl    -4(%ebp), %edx
+       subl    $8, %esp
        pushl   $0
        pushl   $43937
-       pushl   %edx
-       pushl   %eax
        call    __divdi3
        addl    $16, %esp
        leave


-- 
           Summary: libgcc functions and -mregparm don't work well together
           Product: gcc
           Version: 4.3.3
            Status: UNCONFIRMED
          Severity: normal
          Priority: P3
         Component: c
        AssignedTo: unassigned at gcc dot gnu dot org
        ReportedBy: patrick dot georgi at coresystems dot de


http://gcc.gnu.org/bugzilla/show_bug.cgi?id=41055