[Bug c/39985] New: Type qualifiers not actually ignored on function return type
anders at kaseorg dot com
gcc-bugzilla@gcc.gnu.org
Thu Apr 30 23:45:00 GMT 2009
The warning printed with -Wignored-qualifiers (Âwarning: type qualifiers
ignored on function return typeÂ) seems to be lying. The const on a functionÂs
return type is not actually ignored, as can be demonstrated using typeof(). I
think that the warning should be right and the typeof() behavior is wrong, but
IÂm not actually sure.
int f(void);
const int g(void); /* warning: type qualifiers ignored on function return type
*/
typeof(f()) a;
a = 5;
typeof(g()) b;
b = 5; /* error: assignment of read-only variable Âb */
Another thing that seems similarly strange is that a statement expression can
return a const type, even though it is not an lvalue:
const int x = 5;
typeof( ({ x; }) ) y;
y = 5; /* error: assignment of read-only variable Ây */
--
Summary: Type qualifiers not actually ignored on function return
type
Product: gcc
Version: 4.4.0
Status: UNCONFIRMED
Severity: normal
Priority: P3
Component: c
AssignedTo: unassigned at gcc dot gnu dot org
ReportedBy: anders at kaseorg dot com
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=39985
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