[Bug c/38575] free() accept argument that has the same name with standard/builtin function

[pinskia at gcc dot gnu dot org]

------- Comment #1 from pinskia at gcc dot gnu dot org  2008-12-19 03:16 -------
Yes you are passing free a function pointer.  a function decays to a function
pointer and an implicit conversion to void* happens.
If you use -pedantic you get an error message as a function pointer cannot be
converted to void* in standard C:
t.c:4: error: ISO C forbids passing argument 1 of 'free' between function
pointer and 'void *'
/usr/include/stdlib.h:159: note: expected 'void *' but argument is of type 'int
(*)(void)'


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http://gcc.gnu.org/bugzilla/show_bug.cgi?id=38575