[Bug fortran/34143] alloc_comp_constructor.f90 fails with -fdefault-integer-8

[fxcoudert at gcc dot gnu dot org]

------- Comment #4 from fxcoudert at gcc dot gnu dot org  2007-11-20 13:03 -------
The Intel and Sun compilers complain that this code is not legal, because you
can't do "x = mytype(yy, bar)" if yy is not allocated.

Otherwise, a reduced testcase on x86_64-linux is:

  type t
    integer, allocatable :: a(:)
  end type t

  type(t) :: x
  integer(kind=8), allocatable :: yy(:)

  x = t(yy)
  if (allocated(x%a)) print *, "bug"
end


-- 

fxcoudert at gcc dot gnu dot org changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
                 CC|                            |fxcoudert at gcc dot gnu dot
                   |                            |org
             Status|UNCONFIRMED                 |NEW
     Ever Confirmed|0                           |1
   Last reconfirmed|0000-00-00 00:00:00         |2007-11-20 13:03:36
               date|                            |


http://gcc.gnu.org/bugzilla/show_bug.cgi?id=34143