[Bug fortran/30664] New: -pedantic: "Integer outside symmetric range" for integer(1) and (2) does not work

[burnus at gcc dot gnu dot org]

The following program produces no
Warning: Integer outside symmetric range implied by Standard Fortran at (1)

For integer(4) and integer(8) it does (uncomment the '!' lines and see).

(Test case is part of PR 30512.)

-----------------------
program main
implicit none
integer(1) :: i1(3), a1(3:2)
integer(2) :: i2(3), a2(3:2)
!integer(4) :: i4(3), a4(3:2)
logical :: msk(3)
msk = .false.

i1 = 1
i2 = 1
!i4 = 1

if(-huge(i1)-1 /= maxval(i1, msk)) call abort()
if(-huge(a1)-1 /= maxval(a1))      call abort()

if(-huge(i2)-1 /= maxval(i2, msk)) call abort()
if(-huge(a2)-1 /= maxval(a2))      call abort()

!if(-huge(i4)-1 /= maxval(i4, msk)) call abort()
!if(-huge(a4)-1 /= maxval(a4))      call abort()
end program main


-- 
           Summary: -pedantic: "Integer outside symmetric range" for
                    integer(1) and (2) does not work
           Product: gcc
           Version: 4.3.0
            Status: UNCONFIRMED
          Keywords: diagnostic
          Severity: normal
          Priority: P3
         Component: fortran
        AssignedTo: unassigned at gcc dot gnu dot org
        ReportedBy: burnus at gcc dot gnu dot org


http://gcc.gnu.org/bugzilla/show_bug.cgi?id=30664