[Bug driver/31694] New: __GFORTRAN__ preprocessor macro

[fxcoudert at gcc dot gnu dot org]

When preprocessing Fortran code (ie when cc1 is called with -lang-fortran) we
should define a __GFORTRAN__ macro. Here's a patch that does just that:

Index: c-common.h
===================================================================
--- c-common.h  (revision 124116)
+++ c-common.h  (working copy)
@@ -254,6 +254,9 @@
 #define c_dialect_cxx()                (c_language & clk_cxx)
 #define c_dialect_objc()       (c_language & clk_objc)

+/* FXC */
+extern bool lang_fortran;
+
 /* Information about a statement tree.  */

 struct stmt_tree_s GTY(()) {
Index: c-cppbuiltin.c
===================================================================
--- c-cppbuiltin.c      (revision 124116)
+++ c-cppbuiltin.c      (working copy)
@@ -569,6 +569,9 @@
   if (flag_openmp)
     cpp_define (pfile, "_OPENMP=200505");

+  if (lang_fortran)
+    cpp_define (pfile, "__GFORTRAN__=1");
+
   builtin_define_type_sizeof ("__SIZEOF_INT__", integer_type_node);
   builtin_define_type_sizeof ("__SIZEOF_LONG__", long_integer_type_node);
   builtin_define_type_sizeof ("__SIZEOF_LONG_LONG__",
Index: c-opts.c
===================================================================
--- c-opts.c    (revision 124116)
+++ c-opts.c    (working copy)
@@ -73,7 +73,7 @@
 static bool verbose;

 /* If -lang-fortran seen.  */
-static bool lang_fortran = false;
+bool lang_fortran = false;

 /* Dependency output file.  */
 static const char *deps_file;


-- 
           Summary: __GFORTRAN__ preprocessor macro
           Product: gcc
           Version: 4.3.0
            Status: UNCONFIRMED
          Severity: enhancement
          Priority: P3
         Component: driver
        AssignedTo: fxcoudert at gcc dot gnu dot org
        ReportedBy: fxcoudert at gcc dot gnu dot org


http://gcc.gnu.org/bugzilla/show_bug.cgi?id=31694