[Bug middle-end/23673] New: fold does not fold (a^b) != 0 to a != b

[pinskia at gcc dot gnu dot org]

These two functions should be the same on the tree level but are not:
int f(int a, int b)
{
  return (a^b) != 0;
}
int f1(int a, int b)
{
  return a != b;
}

They do result in the same asm though.

Another one from LLVM.

-- 
           Summary: fold does not fold (a^b) != 0 to a != b
           Product: gcc
           Version: 4.1.0
            Status: UNCONFIRMED
          Keywords: missed-optimization, TREE
          Severity: enhancement
          Priority: P2
         Component: middle-end
        AssignedTo: unassigned at gcc dot gnu dot org
        ReportedBy: pinskia at gcc dot gnu dot org
                CC: gcc-bugs at gcc dot gnu dot org


http://gcc.gnu.org/bugzilla/show_bug.cgi?id=23673