[Bug c++/21764] visibility attributes on namespace scope

[bkoz at gcc dot gnu dot org]

------- Comment #5 from bkoz at gcc dot gnu dot org  2005-11-04 17:05 -------
In addition to the current ability to put visibility attributes on file and
class scope, the ability to put visibility attributes on namespace scope is
desired.

The syntax is straight forward extension of existing visibility attribute
options.

namespace test __attribute__ ((visibility("hidden")))
{
  struct c1 
  {
    static int s;
    virtual void foo() { }
  };

  int c1::s;
}

Is an example.

What does this mean? For definitions within namespace scope, set the symbol
visibility to the nearest enclosing namespace attribute. Declarations are
unaffected.

Nested namespaces have the same semantics as nested classes. Ie, enclosing
scope. Therefore:

#define VIS_default __attribute__ ((visibility("default")))
#define VIS_hidden __attribute__ ((visibility("hidden")))

  struct c1 
  {
    static int s;
    virtual void foo() { }

    struct c2 
    {
      static int s;
      virtual void foo() { }
    } VIS_default;
  } VIS_hidden;

namespace test1 VIS_hidden
{
  struct c1 
  {
    static int s;
    virtual void foo() { }
  };

  int c1::s;

  namespace test2 VIS_default
  {
    struct c2 
    {
      static int s;
      virtual void foo() { }
    };

    int c2::s;
  }
}

In the above, struct c2 and test1::test2::c2 both have default visibility,
whereas c1 and test1::c1 both have hidden visibility.

Interactions between file, namespace, and class scope are handled sanely. Ie,
the same deal, nearest enclosing scope.

ie:

#pragma GCC visibility push(hidden)

namespace test1 VIS_default
{
  struct c1 
  {
    static int s;
    virtual void foo() { }
  };

  int c1::s;

  struct c2 
  {
    static int s;
    virtual void foo() { }
  } VIS_hidden;

  int c2::s;
}

#pragma GCC visibility pop

In the above, c1 would be default, c2 would be hidden.


-- 


http://gcc.gnu.org/bugzilla/show_bug.cgi?id=21764