[Bug c++/19665] New: Can access private member function if it is virtual

amit_choudhary at mindtree dot com gcc-bugzilla@gcc.gnu.org
Fri Jan 28 09:20:00 GMT 2005


I was doing some experiments and I discovered that I can access a private member
function if I make it virtual and do few other tricks. The code is below.

The "Base class called" is printed. So, basically when someone wants to access 
a virtual function (by explicit type casting), there is no check whether that
virtual function is private or not. But if I try to call it directly, it checks
that it is a private member function. May be g++ compiler needs to be modified.


#include<iostream>

using namespace std;

class A {
private:
        virtual void abc()
        {
                cout << "Base Class called\n";
        }
};

class B : public A {
public:
        void abc()
        {
                cout << "Derived Class called\n";
        }
};

int main()
{
        A a;
        B *b = static_cast<B *>(&a);
        b->abc();
}

[amit]$ g++ c++-bug.cpp
c++-bug.cpp:6: warning: all member functions in class `A' are private
[amit]$ ./a.out
Base Class called
[amit]$

-- 
           Summary: Can access private member function if it is virtual
           Product: gcc
           Version: 3.3.3
            Status: UNCONFIRMED
          Severity: normal
          Priority: P2
         Component: c++
        AssignedTo: unassigned at gcc dot gnu dot org
        ReportedBy: amit_choudhary at mindtree dot com
                CC: gcc-bugs at gcc dot gnu dot org
 GCC build triplet: g++ c++-bug.cpp c++-bug.cpp:6: warning: all member
                    functions in
  GCC host triplet: gcc version 3.3.3 20040412 (Red Hat Linux 3.3.3-7)
GCC target triplet: Configured with: ../configure --prefix=/usr --
                    mandir=/usr/share/


http://gcc.gnu.org/bugzilla/show_bug.cgi?id=19665



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