[Bug target/19945] Inefficient store of constant into a global register

[steven at gcc dot gnu dot org]

------- Additional Comments From steven at gcc dot gnu dot org  2005-02-14 00:49 -------
This is not wasting a register at all, don't make unfounded claims like that 
if you don't know why exactly the code looks like it does. 
 
In this case the code comes from a peephole2 splitting the immediate move.  
Those peepholes run after register allocation, so the peephole can only apply 
if a register is available.  If there are no available registers, the peephole 
simply does not match. 
 
So in fact this peephole makes gcc use the registers more efficiently! 

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http://gcc.gnu.org/bugzilla/show_bug.cgi?id=19945