[Bug c++/21246] New: Compiler fails when using and incrementing a variable i: f(i,++i) equivalent to f(i+1,i+1); ++i
jandres at dsic dot upv dot es
gcc-bugzilla@gcc.gnu.org
Wed Apr 27 07:37:00 GMT 2005
The next code, should show int the screen "a:2 b:3"; but shows "a:3 b:3".
I have tested it into several versions from 3.3 to 4.0. Always the same result.
void foo(int a,int b)
{
std::cout<<"a:"<<a<<" b:"<<b<<std::endl;
}
int main()
{
int n=2;
foo(n,++n);
}
--
Summary: Compiler fails when using and incrementing a variable i:
f(i,++i) equivalent to f(i+1,i+1); ++i
Product: gcc
Version: 4.0.0
Status: UNCONFIRMED
Severity: normal
Priority: P1
Component: c++
AssignedTo: unassigned at gcc dot gnu dot org
ReportedBy: jandres at dsic dot upv dot es
CC: gcc-bugs at gcc dot gnu dot org
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=21246
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