[Bug c++/20976] when terminate is called, stack is not unwinded
pinskia at gcc dot gnu dot org
gcc-bugzilla@gcc.gnu.org
Tue Apr 12 19:23:00 GMT 2005
------- Additional Comments From pinskia at gcc dot gnu dot org 2005-04-12 19:23 -------
Ok, this is just implemenation defined behavior.
see 15.3 P 9:
If no matching handler is found in a program, the function terminate() is called; whether or not the
stack is unwound before this call to terminate() is implemenation-defined (15.5.1)
So we define it as not unwinding but we don't document this.
Confirmed for documentation.
--
What |Removed |Added
----------------------------------------------------------------------------
Status|UNCONFIRMED |NEW
Ever Confirmed| |1
Keywords| |documentation
Last reconfirmed|0000-00-00 00:00:00 |2005-04-12 19:23:16
date| |
Summary|when exceptions are not |when terminate is called,
|caught, destructors of local|stack is not unwinded
|vars are not executed |
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=20976
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