[Bug c++/17507] Problems with shift and increment operator precedence

[work at paul dot dubuc dot org]

------- Additional Comments From work at paul dot dubuc dot org  2004-09-15 20:30 -------
(In reply to comment #6)
> As for question 1) The standard says that the result is undefined, i.e. 
> the compiler can do whatever it pleases. That includes doing one of 
> the increments, four in the same order in which the appear left to 
> right, four in the reverse order, etc. It isn't a bug, but an opportunity 
> the standard leaves to the compiler writers to implement optimizations.

Regardless of the order that the increment is done in this statement, I would
expect it to be done 4 times (not only once) by the time the statement ends.
 
>  
> As for 2) the result is still undefined, and the fact that you get what 
> you expect can be attributed to luck. 

I can accept this, I guess, if nothing in the Standard says the undefined
behavior must be consistent.


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http://gcc.gnu.org/bugzilla/show_bug.cgi?id=17507