[Bug rtl-optimization/2962] inefficient code with and

[rth at gcc dot gnu dot org]

------- Additional Comments From rth at gcc dot gnu dot org  2004-09-13 03:37 -------
Note that either movzbl or movzwl is required on i686 to avoid a
partial register stall.  Which is why things are generated this way.
It would perhaps be possible to avoid this for earlier processors,
but I don't believe this is worth the effort.

-- 


http://gcc.gnu.org/bugzilla/show_bug.cgi?id=2962