[Bug libfortran/16137] Fortran compiler unable to produce executables as libfortran depends on C99 math functions

[ro at techfak dot uni-bielefeld dot de]

------- Additional Comments From ro at techfak dot uni-bielefeld dot de  2004-06-24 17:35 -------
Subject: Re:  Fortran compiler unable to produce executables as libfortran depends on C99 math functions

"sgk at troutmask dot apl dot washington dot edu" <gcc-bugzilla@gcc.gnu.org> writes:

> gfortran works on FreeBSD, which does not use glibc.  In fact, if

... and it probably would on other platforms which include a full ISO C99
libc.  Unfortunately, of the platforms I regularly work on (Solaris 2,
Tru64 UNIX, IRIX), only Solaris 10 and IRIX 6.5.18+ have an ISO C99 libc,
and even that one isn't fully usable with GCC due to the use of
vendor-compiler specific builtins in the system headers.  I wasn't fully
aware about the situation with the various BSDs; thanks for setting me
straight.

> On the other hand, you have a point that gfortran should not 
> unconditionally assume a C99 compiler.  Indeed, Bud Davis
> recently committed c99-functions.c to provide a compatibility
> shim.  If you have any patches, please send then to fortran@

Not at the moment: time for gcc work is far too limited right now, and I
stopped including gfortran when it either wouldn't even build on my
platforms for various reasons (mostly mentioned in PRs) or all test cases
failed with link failures.

	Rainer


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http://gcc.gnu.org/bugzilla/show_bug.cgi?id=16137