[Bug c++/16610] constructor template binding different than plain function for same types

[igodard at pacbell dot net]

------- Additional Comments From igodard at pacbell dot net  2004-07-17 22:58 -------
There isn't anything in the standard that would cause constructor templates to bind differently than plain functions, is there?

Incidentally, the array call is recognized only on global functions. Member functions and static members all think it's a reference:

#include    <iostream>
template<typename T>
void Foo(T t) { std::cout << "any\n"; }
template<typename T>
void Foo(T*const& t) { std::cout << "reference\n"; }
template<typename T, size_t s>
void Foo(T(&t)[s]) { std::cout << "array\n"; }
template<typename T>
struct Frob {
    Frob(T*const& t) { std::cout << "reference\n"; }
    template<size_t s>
    Frob(T(&t)[s]) { std::cout << "array\n"; }
    void Bar(T*const& t) { std::cout << "reference\n"; }
    template<size_t s>
    void Bar(T(&t)[s]) { std::cout << "array\n"; }
    static void Baz(T*const& t) { std::cout << "reference\n"; }
    template<size_t s>
    static void Baz(T(&t)[s]) { std::cout << "array\n"; }
    };

int main() {
    int* ri;
    int ra[10];
    Foo(ri);
    Foo(ra);
    Foo(new int[2]);
    Frob<int> f1(ri);
    Frob<int> f2(ra);
    Frob<int> f3(new int[2]);
    Frob<int> f4 = ri;
    Frob<int> f5 = ra;
    Frob<int> f6 = new int[2];
    f1.Bar(ri);
    f1.Bar(ra);
    Frob<int>::Baz(ri);
    Frob<int>::Baz(ra);
    }


gives:

~/ootbc/members/members/sweetie/test/src$ a.out
reference
array
reference
reference
reference
reference
reference
reference
reference
reference
reference
reference
reference


Ivan


-- 


http://gcc.gnu.org/bugzilla/show_bug.cgi?id=16610