[Bug c++/15083] New: spurious "statement has no effect" warning
carlton at bactrian dot org
gcc-bugzilla@gcc.gnu.org
Thu Apr 22 23:23:00 GMT 2004
When I compile the following program with g++ -Wall (where g++ is the
released 3.4.0), I get the following warning:
quartette$ /net/quartette/carlton/gcc/gcc-3.4.0/install/bin/g++ -Wall test.cpp
test.cpp: In member function `void Foo<T>::resetData()':
test.cpp:31: warning: statement has no effect
The line in question is this one:
new ( refLoc ) Counter();
but Counter's contructor does have a side effect. (Indeed, the output
of the program changes if you compile out that line.)
Here's the source code; I'll attach a .ii file as well. (The .ii
file is kind of large, because I include <iostream> to show that
the line in question does indeed change the behavior of the program.)
#include <new>
#include <iostream>
class Counter {
public:
void decrement() { --ref_; }
Counter() : ref_(1) {}
int ref() const {
return ref_;
}
private:
int ref_;
};
template< typename T >
class Foo {
public:
void resetData() {
ref_.decrement();
std::cout << "before: " << ref_.ref() << std::endl;
ref_.~Counter();
void *refLoc = &ref_;
// GCC erroneously claims that the following line has no
// effect. But it does have an effect: the value of the
// "after" message will be 0 instead of 1 if you comment it
// out.
new ( refLoc ) Counter();
std::cout << "after: " << ref_.ref() << std::endl;
}
private:
Counter ref_;
};
int main() {
Foo< int > node;
node.resetData();
}
--
Summary: spurious "statement has no effect" warning
Product: gcc
Version: 3.4.0
Status: UNCONFIRMED
Severity: normal
Priority: P2
Component: c++
AssignedTo: unassigned at gcc dot gnu dot org
ReportedBy: carlton at bactrian dot org
CC: gcc-bugs at gcc dot gnu dot org
GCC build triplet: i686-pc-linux-gnu
GCC host triplet: i686-pc-linux-gnu
GCC target triplet: i686-pc-linux-gnu
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=15083
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