[Bug c++/12471] New: functions shown as ?? in gdb

[gcc-bugzilla at gcc dot gnu dot org]

PLEASE REPLY TO gcc-bugzilla@gcc.gnu.org ONLY, *NOT* gcc-bugs@gcc.gnu.org.

http://gcc.gnu.org/bugzilla/show_bug.cgi?id=12471

           Summary: functions shown as ?? in gdb
           Product: gcc
           Version: 3.3
            Status: UNCONFIRMED
          Severity: normal
          Priority: P3
         Component: c++
        AssignedTo: unassigned at gcc dot gnu dot org
        ReportedBy: xu at cs dot wisc dot edu
                CC: gcc-bugs at gcc dot gnu dot org
 GCC build triplet: sparc-sun-solaris2.8
  GCC host triplet: sparc-sun-solaris2.8
GCC target triplet: sparc-sun-solaris2.8

	If you compile the following simple program and debug it with gdb 5.3
64bit version, everything works fine except that when you press ^C and stop in
the gdb prompt and do a "where" command. You will not see the function names of
the c++ library. I have tried other calls and gdb was able to show function
name of /usr/lib/libc.so, for instance. I am not sure this is a bug of gcc or
gdb, I shall report to both.

Environment:
System: SunOS pinot.cs.wisc.edu 5.8 Generic_108528-23 sun4u sparc SUNW,Sun-Fire-880
Architecture: sun4

	
host: sparc-sun-solaris2.8
build: sparc-sun-solaris2.8
target: sparc-sun-solaris2.8
configured with: ../gcc-3.3/configure --prefix=/s/gcc-3.3 --enable-threads --enable-shared

How-To-Repeat:
	For the following code:

#include <iostream>
using namespace std;

main() {
  cout << "helo" << endl;
  for(;;) {
    cout << "a";
  }
}

	compile with
  g++ -g -m64 -mcpu=v9 -ldl test.cc
	debug with
  gdb a.out
	in gdb
  run
  ^c
  where
------- Additional Comments From xu at cs dot wisc dot edu  2003-10-01 02:30 -------
Fix:
	if you know, let me know.