c++/10694: [3.3/3.4 regression] Befriending a function in a class that is only forward-declared
Steven Bosscher
s.bosscher@student.tudelft.nl
Sun May 11 11:16:00 GMT 2003
http://gcc.gnu.org/cgi-bin/gnatsweb.pl?cmd=view%20audit-trail&database=gcc&pr=10694
: Search converges between 2003-03-10-trunk (#149) and 2003-03-11-trunk
(#150).
Line-numbered input is:
========================================
1 template <class T> struct Y;
2
3 template <class S> class X {
4 template <class T> friend void Y<T>::member();
5 };
6
7 template <class T> struct Y {
8 void member() {
9 X<int>();
10 }
11 };
12
13 template class Y<int>;
14
========================================
Diagnostic output follows, from the last compiler tested:
input: In instantiation of `X<int>':
input:9: instantiated from `void Y<T>::member() [with T = int]'
input:13: instantiated from here
input:4: error: prototype for `template<class T> void Y::member()' does not
match any in class `Y<T>'
input:8: error: candidate is: void Y<T>::member()
Compiler output follows, from the last compiler tested:
.file "input"
.ident "GCC: (GNU) 3.4 20030311 (experimental)"
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