[Bug c++/11684] New: Template specialisation

nickn at newsonnet dot fsnet dot co dot uk gcc-bugzilla@gcc.gnu.org
Sun Jul 27 15:07:00 GMT 2003


PLEASE REPLY TO gcc-bugzilla@gcc.gnu.org ONLY, *NOT* gcc-bugs@gcc.gnu.org.

http://gcc.gnu.org/bugzilla/show_bug.cgi?id=11684

           Summary: Template specialisation
           Product: gcc
           Version: 3.3
            Status: UNCONFIRMED
          Severity: normal
          Priority: P2
         Component: c++
        AssignedTo: unassigned at gcc dot gnu dot org
        ReportedBy: nickn at newsonnet dot fsnet dot co dot uk
                CC: gcc-bugs at gcc dot gnu dot org

The following example seems to instance the templated function incorrectly:

class test
{
public:
 float operator[]( int index )
 {
  return testFloat[index];
 }
private:
 float testFloat[3];
};

template < class typeA > float
operator*(
 typeA a,
 float b
)
{
 return a[0] * b;
}

template < class typeB > float
operator*(
 float a,
 typeB b
)
{
 return a * b[0];
}

template < class typeA, class typeB > float
operator*(
 typeA a,
 typeB b
)
{
 return a[0] * b[0];
}

int main( void )
{
 test aTest;
 float bTest;
 float result;

 result = aTest * bTest;
 result = bTest * aTest;

 return 0;
}

with the errors:

test.cpp:31: `float operator*(float, typeB) [with typeB = float]' must have
an argument of class or enumerated type
test.cpp:22: `float operator*(typeA, float) [with typeA = float]' must have
an argument of class or enumerated type

Surely if the operation is float * class the the more specialised template
is the float, typeB version, not the typeA, float version?



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