[ECOS] Re: casts to a type other than an integral or enumeration type in a constant-expression
Thu Feb 13 13:56:00 GMT 2003
Jonathan Larmour wrote:
> Indeed it's like that. But the whole thing is cast to an int, so the
> expression as a whole has integral type. From the C++ standard 6.4.2
> para 2 that's all that's required, the way I read it. Having a
> non-integral type in an intermediate stage should make no difference.
you are incorrect. [5.19] says quite clearly what an integral constant
expression can involve. A cast to a function pointer is not one of them.
Nathan Sidwell :: http://www.codesourcery.com :: CodeSourcery LLC
The voices in my head said this was stupid too
firstname.lastname@example.org : http://www.cs.bris.ac.uk/~nathan/ : email@example.com
More information about the Gcc-bugs