libstdc++/5457: Writing to buffer stream writes each byte using a system write() call.

emaros@ligo.caltech.edu emaros@ligo.caltech.edu
Tue Jan 22 13:46:00 GMT 2002


>Number:         5457
>Category:       libstdc++
>Synopsis:       Writing to buffer stream writes each byte using a system write() call.
>Confidential:   no
>Severity:       serious
>Priority:       medium
>Responsible:    unassigned
>State:          open
>Class:          pessimizes-code
>Submitter-Id:   net
>Arrival-Date:   Tue Jan 22 13:46:05 PST 2002
>Closed-Date:
>Last-Modified:
>Originator:     emaros@ligo.caltech.edu
>Release:        gcc-3.0.3
>Organization:
>Environment:
RedHat 7.2 Linux/Intel
Reading specs from /ldcg/lib/gcc-lib/i686-pc-linux-gnu/3.0.3/specs
Configured with: ../configure --prefix=/ldcg --with-prefix=/ldcg --enable-long-long
Thread model: single
gcc version 3.0.3
>Description:
When writing to cout, each character is being written via
the system write() call.Ouput of strace:

...
fstat64(1, {st_mode=S_IFCHR|0620, st_rdev=makedev(136, 7), ...}) = 0
mmap2(NULL, 4096, PROT_READ|PROT_WRITE, MAP_PRIVATE|MAP_ANONYMOUS, -1, 0) = 0x40206000
ioctl(1, TCGETS, {B38400 opost isig icanon echo ...}) = 0
write(1, "H", 1H)                        = 1
write(1, "e", 1e)                        = 1
write(1, "l", 1l)                        = 1
write(1, "l", 1l)                        = 1
write(1, "o", 1o)                        = 1
write(1, " ", 1 )                        = 1
write(1, "W", 1W)                        = 1
write(1, "o", 1o)                        = 1
write(1, "r", 1r)                        = 1
write(1, "l", 1l)                        = 1
write(1, "d", 1d)                        = 1
write(1, "!", 1!)                        = 1
write(1, "\n", 1
)                       = 1
munmap(0x40206000, 4096)                = 0
_exit(0)                                = ?
>How-To-Repeat:
g++ t.cc
strace ./a.out
>Fix:

>Release-Note:
>Audit-Trail:
>Unformatted:
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