c++/4003: ICE on template instantiation including friendship declaration.

[gdr@codesourcery.com]

>Number:         4003
>Category:       c++
>Synopsis:       ICE on template instantiation including friendship declaration.
>Confidential:   no
>Severity:       serious
>Priority:       high
>Responsible:    unassigned
>State:          open
>Class:          ice-on-legal-code
>Submitter-Id:   net
>Arrival-Date:   Sat Aug 11 03:46:05 PDT 2001
>Closed-Date:
>Last-Modified:
>Originator:     Gabriel Dos Reis (gdr@codesourcery.com)
>Release:        GCC-3.0.1 and GCC-3.1
>Organization:
>Environment:
Immaterial
>Description:
The below produces an ICE.  A regression over gcc-2.95.x
>How-To-Repeat:

>Fix:

>Release-Note:
>Audit-Trail:
>Unformatted:
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template<typename> class BinaryTree;

template<typename T>
void move(BinaryTree<T>&, typename BinaryTree<T>::iterator,
          BinaryTree<T>&, typename BinaryTree<T>::iterator);

template<class T>
class BinaryTree {
public:
  class iterator {
  private:
    int i;
    friend void move<T>(BinaryTree<T> &t1,iterator n1,
                       BinaryTree<T> &t2,iterator n2);
  };
};


template<class T>
inline void move(BinaryTree<T> &t1, typename BinaryTree<T>::iterator n1,
                 BinaryTree<T> &t2, typename BinaryTree<T>::iterator n2)
{
  int x = n1.i + n2.i;    // this is the line that uses the friendship
}

int main() {
  typedef BinaryTree<int> BT;
  BT t;
  BT::iterator n;
  move(t, n, t, n);
}