C++ using declaration for a template method

[Paolo Calafiura]

Hi guys,
 the following does not compile - as I believe it should - using gcc 3.0 or even
the head of 3.1 


#include <iostream>
using namespace std;
class Base {
public:
  template <typename Foo>
  void useFoo(Foo foo) {cout << "useFoo prints " << foo << endl;}//line #6
 
  void useInt(int i) {cout << "useInt prints " << i << endl;}

};

class Derived: private Base {
public:
  using Base::useInt;
  using Base::useFoo;
};

int main() {
  Derived d;
  int i(1);
  d.useInt(i);
  d.useFoo(i);   //line #22
  return 0;
}


GCC Output:

[test]$ uname -a      
Linux ------- 2.4.7-ac1 #37 Sat Aug 4 10:32:54 PDT 2001 i686 unknown

[test]$ g++ -v
Reading specs from /usr/local/lib/gcc-lib/i686-pc-linux-gnu/3.1/specs
Configured with: ../gcchead/configure --enable-languages=c++,f77,java
Thread model: single
gcc version 3.1 20010810 (experimental)

[test]$ g++ using.cxx
using.cxx: In function `int main()':
using.cxx:6: `void Base::useFoo(Foo) [with Foo = int]' is inaccessible
using.cxx:22: within this context

 
I have found a similar bug report
http://gcc.gnu.org/ml/gcc-bugs/2001-08/msg00146.html
posted few days ago and a later message msg00178.html saying it has been
fixed in 3.1 sources. 

Paolo

FIY with KCC 4.0 the code above compiles and runs as I expected...