gcc bug

[Nathan Sidwell]

Pawel Palucha wrote:

> Perhaps I'm wrong, but I though that "unsigned long k = 1UL << 32" is the
> same as "int i = 32; unsigned long k = 1UL << i".
No. `expr << shift' invokes undefined behaviour when `shift' is negative
or greater or equal to the length in bits of `expr'. You have 32bit
longs, so have invoked undefined behaviour -- anything can happen.

nathan
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