[g++ 2.95.2] template and assignment operator
Alexandre Duret-Lutz
alexandre.duret@greyc.ismra.fr
Thu Nov 4 08:58:00 GMT 1999
Hi people,
I can't decide wether this is bad or not. Consider:
#include <iostream>
template< typename T >
struct A {
template< typename U >
A<T>& operator=( const U& u ) {
cout << "hello" << endl;
return *this;
}
};
int main()
{
A<char> a,b;
a = 1; // prints "hello"
a = b; // prints nothing
}
For this last instruction, it look like the default assignment
operator was prefered to the template. Is this behaviour really
correct? I can't see why.
Regards,
--
Alexandre Duret-Lutz
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