wrong operator=() taken

[Alexandre Oliva]

On Aug 24, 1999, "Marc Winter (HiWi)" <marcw@nick-5.neuro.informatik.uni-kassel.de> wrote:

> 	A::operator=

> I think the output should have been:
	
> 	C::operator=

Nope.  An `operator=(const C&)' is implicitly generated for C<T>, and
it is preferred over `operator=(const A<T>&)' in overload resolution.
It calls B's `operator=(const B&)', also implicitly defined, and this
one calls A's `operator=(const A&)'.

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Alexandre Oliva http://www.dcc.unicamp.br/~oliva IC-Unicamp, Bra[sz]il
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